Question

What is the value of $tan\theta$ in $△$ABC, if $\theta$ is increased by ${30}^{\circ }$.

• A. $\sqrt{3}$
• B. $\frac{1}{\sqrt{3}}$
• C. Not defined.

Answer 1

The correct option is C Not defined.

In $△ABC$, if $\theta$ is increased by ${30}^{\circ }$, then $\theta ={30}^{\circ }+{30}^{\circ }={60}^{\circ }$.
$\because tan{60}^{\circ }=\sqrt{3}$
$\therefore tan\theta =tan{60}^{\circ }=\sqrt{3}$