What is the value of the expression 12÷3+3×(6−7)314159?
A
−2
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B
−1
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C
1
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D
5
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E
7
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Solution
The correct option is B1 In BODMAS rule we do multiplication first and then addition We know that, 1 to the power anything is 1 Given, =12÷3+3×(6−7)314159 =4+3×(−1)314159 =4+3×−1 =4−3=1