Question

What is the value of the expression $\frac{\cos \left({90}^0+\theta \right)\sec \left(-\theta \right)\tan \left({180}^0-\theta \right)}{\sec \left({360}^0-\theta \right)\sin \left({180}^0+\theta \right)\cot \left({90}^0-\theta \right)}?$

• A. $\pi$
• B. $\frac{\pi }{2}$
• C. $0$
• D. $-1$

Answer 1

The correct option is D $-1$

$\frac{\cos \left({90}^0+\theta \right)\sec \left(-\theta \right)\tan \left({180}^0-\theta \right)}{\sec \left({360}^0-\theta \right)\sin \left({180}^0+\theta \right)\cot \left({90}^0-\theta \right)}$

$\frac{\sin \theta \sec \theta (-\tan \theta )}{\sec \theta (-\sin \theta )(-\tan \theta )}$

$⟹-1$