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First Order Reaction

What is the v...

Question

What is the value of the ratio $t_{7 / 8}$ / $t_{1 / 2}$ for a first order reaction?

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Solution

The correct option is A 3
$[A] = {[A]}_{0} e x p (- k t) f o r t = t_{1 / 2}, [A] = {[A]}_{0} / 2 t_{1 / 2} = \frac{l n 2}{k} f o r t = t_{7 / 8}, [A] = {[A]}_{0} / 8 t_{7 / 8} = \frac{l n 8}{k} = \frac{3 l n 2}{k} \frac{t_{7 / 8}}{t_{1 / 2}} = 3$

Suggest Corrections

Similar questions

t_{7 / 8} = n \times t_{1 / 2}

n

t_{1 / 2}

t_{1 / 2}

t_{7 / 8}

2 A + B

\to

C + D

(t_{1 / 2})

t_{7 / 8}

[\frac{b}{a} - \frac{d}{c}]

a, b, c

d

t_{1 / 8}

t_{1 / 10}

\frac{[t_{1} / 8]}{[t_{1} / 10]} \times 10 ? (l o g_{10} 2 = 0.3)

\frac{1}{8}

\frac{1}{10}

\frac{t_{1}}{8}

\frac{t_{1}}{10}

\frac{[\frac{t_{1}}{8}]}{[\frac{t_{1}}{10}]} \times 10 ? ({log}_{10} 2 = 0.3)

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