Question

What is the value of the reflex angle formed between the hands of a clock at 10:25?

• A.
• B.
• C.
• D.
• E.

Answer 1

The correct option is E

Angle traced by hour hand in $(10+\frac{25}{12})$hours = ${(\frac{360}{12}\times \frac{125}{12})}^0=312{\frac{1}{2}}^0$

Angle traced by minute hand in $25$ minutes = ${(\frac{360}{60}\times 25)}^0={150}^0$

$\therefore$Reflex angle = ${360}^0$ - ${(312\frac{1}{2}-150)}^0={360}^0-162{\frac{1}{2}}^0=197{\frac{1}{2}}^0$