What is the value of unknown resistor R in Fig- If the voltage drop across the 500 - resistor is 2-5V- All resistances are in ohms-

i =2.5500 = 5 mA #10; #10; #160; #160; #160; #10; V_CD = 5 × #160; 10^ 3 #10;× 550 #10; #10; #160; #160; #160; #160; #1 ...

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Standard XII

Physics

RLC Circuit

What is the v...

Question

What is the value of unknown resistor R in Fig. If the voltage drop across the $500 Ω$ resistor is 2.5V? All resistances are in ohms.

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Solution

$i = \frac{2.5}{500} = 5 m A$

$V_{C D} = 5 \times 10^{- 3} \times 550$

$= 2.75$

Voltage divide rule –

$V_{C D} = \frac{12 \times (550 | | R)}{550 | | R + 550}$

$2.75 = \frac{12 \times 550 \times R}{550 \times R + 550 (R + 550)}$
$(2.75) (2 R + 550) = 12 R$
$R = 232.69 Ω$ .

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What is the value of unknown resistor R in Fig. If the voltage drop across the 500Ω resistor is 2.5V? All resistances are in ohms.

i=2.5500=5mA VCD=5×10−3×550 =2.75 Voltage divide rule – VCD=12×(550||R)550||R+550 2.75=12×550×R550×R+550(R+550) (2.75)(2R+550)=12R R=232.69Ω .

What is the value of unknown resistor R in Fig. If the voltage drop across the $500 Ω$ resistor is 2.5V? All resistances are in ohms.

$i = \frac{2.5}{500} = 5 m A$

$V_{C D} = 5 \times 10^{- 3} \times 550$

$= 2.75$

Voltage divide rule –

$V_{C D} = \frac{12 \times (550 | | R)}{550 | | R + 550}$

$2.75 = \frac{12 \times 550 \times R}{550 \times R + 550 (R + 550)}$
$(2.75) (2 R + 550) = 12 R$
$R = 232.69 Ω$ .