What is the value of $x$ for which the following equation is true?
$\frac{1}{x + 3} = \frac{3}{4 x}$

x = 4

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x = 6

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x = - 9

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x = 9

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Solution

The correct option is D $x = 9$
$\frac{1}{x + 3} = \frac{3}{4 x}$
$4 x \times 1 = 3 \times (x + 3)$
$4 x = 3 x + 9$
$4 x - 3 x = 9$
$x = 9$

Hence, the value of $x$ is 9.

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