The correct option is C 3
Given,
LHS = 5x−312
and RHS = 1
Using trial and error method,
Case 1:
Putting x=1,
LHS = 5×1−312 = 5−312 = 212 = 16
Hence, LHS is not equal to RHS.
Case 2:
Putting x=2,
LHS = 5×2−312 = 10−312 = 712
Hence, LHS is not equal to RHS.
Case 3:
Putting x=3,
LHS = 5×3−312 = 15−312 = 1212 = 1
Hence, LHS is equal to RHS.
∴ x = 3 is the solution for given algebraic equation.