What is the value of X in the following equation- x0-4- 16-32- x2-6-

The correct option is B 8 x^0.4÷ 16=32÷ x^2.6 ⇒ #160; x^0.416=32x^2.6 ⇒ #160; x^0.4× x^2.6=32× 16 ⇒ #160; x^0. ...

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Standard VIII

Mathematics

Inverse Proportion

What is the v...

Question

What is the value of (X) in the following equation?
$x^{0.4} \div 16 = 32 \div x^{2.6}$ .

8

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Solution

The correct option is B $8$
$x^{0.4} \div 16 = 32 \div x^{2.6}$

$\Rightarrow$ $\frac{x^{0.4}}{16} = \frac{32}{x^{2.6}}$

$\Rightarrow$ $x^{0.4} \times x^{2.6} = 32 \times 16$

$\Rightarrow$ $x^{0.4 + 2.6} = 512$ [ $a^{m} \times a^{n} = a^{m + n}$ ]

$\Rightarrow$ $x^{3} = 512$
Now, taking cube root on both sides,
$∴$ $x = 8$

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Similar questions

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

Q. The value of

\frac{18^{3} + 7^{3} + 3 \cdot 18 \cdot 7 \cdot 25}{3^{6} + 6 \cdot 243 \cdot 2 + 15 \cdot 181 \cdot 4 + 20 \cdot 27 \cdot 8 + 15 \cdot 9 \cdot 16 + 6 \cdot 3 \cdot 32 + 64}

Find the value of
$\frac{(18^{3} + 7^{3} + 3 \cdot 18 \cdot 7 \cdot 25)}{3^{6} + 6 \cdot 243 \cdot 2 + 15 \cdot 81 \cdot 4 + 20 \cdot 27 \cdot 8 + 15 \cdot 9 \cdot 16 + 6 \cdot 3 \cdot 32 + 64}$

$\begin{matrix} Class intervals & 0 - 8 & 8 - 16 & 16 - 24 & 24 - 32 & 32 - 40 Frequency & 7 & 12 & 15 & 9 & 6 \end{matrix}$

Represent the given data using suitable graphical representation.

Q. What is the value of

x

in the given equation?

\frac{(3 x + 1)}{16} + \frac{(2 x - 3)}{7} = \frac{(x + 3)}{8} + \frac{(3 x - 1)}{14}

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What is the value of (X) in the following equation?x0.4÷16=32÷x2.6.

The correct option is B 8x0.4÷16=32÷x2.6⇒ x0.416=32x2.6⇒ x0.4×x2.6=32×16⇒ x0.4+2.6=512 [ am×an=am+n ]⇒ x3=512Now, taking cube root on both sides,∴ x=8

What is the value of (X) in the following equation?
$x^{0.4} \div 16 = 32 \div x^{2.6}$ .