What is the value of x is equals to root 6 + root 6 + root 6 + root 6 upto infinity?
Let us assume : x= root(6+root(6 + root(6 + ………
So,
x= root(6+x)
x^2=6+x
x^2-x-6=0
(x-3)(x+2)=0
So, x=3 or -2.
x is positive ie root 6 + root 6 + root 6 + root 6 upto infinity is positive
then we discard x=-2
So the answer is x =3.