Question

What is the value of $x$ where: $x=9.4g+6.023\times {10}^{23}molecules-0.2mol$. $x$ is phenol which has a molar mass of $94g/mol$.

• A. $0.9$ mol
• B. $9.2$ g
• C. $1.3$ mol
• D. $0.1$ mol

Answer 1

The correct option is A $0.9$ mol

Since most of the options are in moles, let us calculate the value of 'x' in terms of mole.

$9.4$ gm phenol = $\frac{9.4}{94}$ = $0.1$ mol
$6.023\times {10}^{23}$ molecules of phenol = $\frac{6.023\times {10}^{23}}{6.023\times {10}^{23}}$ = $1$ mol
Then, we subtract $0.2$ mol phenol:
Hence 'x' = $0.1+1-0.2$ = $0.9$ mol phenol