The correct option is B 15∘,18∘
AB is diameter of the circle.
In △ADB,
m∠BDA=90∘
(angle subtended by diameter AB on point D will be 90∘)
⇒x∘+5x∘+90∘=180∘
6x∘=90∘
∴x=15∘
Now,
In △ACB,
m∠ACB=90∘
(angle subtended by diameter AB on point C will be 90∘)
⇒3y∘+2y∘+90∘=180∘
5y∘=90∘
∴y=18∘