What is the vapour density of ethylene- Avogadro-s number -6 - 1023- Atomic weight of C -12- H -1- Molar volume -22-4 litres at STPA- 19B- 14C- 24D- 16E- 12

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Standard IV

Mathematics

Long Division Method

What is the v...

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What is the vapour density of ethylene?

(Avogadro's number = 6 x 10²³; Atomic weight of C = 12, H = 1; Molar volume = 22.4 litres at STP)

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Solution

The correct option is E
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(a) Calculate the number of moles and number of molecules present in 1.4 g of ethylene gas. What is the volume occupied by the same amount of ethylene?
(b) What is the vapour density of ethylene?
(Avogadro's number = 6 × 10²³; Atomic weight of C = 12, H = 1; Molar volume = 22.4 litres at STP)

(a)

(i) Calculate the volume of 320 of $S O_{2}$ at STP. (Atomic mass : S = 32 and O = 16).
(ii) State Gay-Lussac's law of combining volume
(iii) Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane $(C_{3} H_{8})$ (Atomic mass; C = 12, 0 = 16, H = 1, Molar volume $- 22.4 d m^{3}$

(b)

(i) An organic compound with vapour density = 94 contains
C = 12.67% H = 2.13 % and Br = 85.11% Find the molecular formula.
[Atomic mass ; C = 12, H = 1, Br = 80]
(ii) Calculate the mass of
(1) $10^{22}$ Atoms of sulphur.
(2) 0.1 mole of carbon dioxide.
[Atomic mass; S = 32, C = 12 and O = 16 and Avogadro's number $= 6 \times 10^{23}$

Define the terms:
(a) vapour density
(b) molar volume
(c) relative atomic mass
(d) Avogadro's number
(e) relative molecular mass

The vapour density of a gas is 11.2. What is the volume occupied by 10g of the gas at STP?

Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane (C₃H₈).

[Atomic mass: C = 12, O = 16, H = 1, Molar volume = 22.4 dm³ at stp]

5.20 litres

3.50 litres

2.58 litres

4.48 litres

1.99 litres

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What is the vapour density of ethylene? (Avogadro's number = 6 x 1023; Atomic weight of C = 12, H = 1; Molar volume = 22.4 litres at STP)

The correct option is E 14

What is the vapour density of ethylene?

(Avogadro's number = 6 x 10²³; Atomic weight of C = 12, H = 1; Molar volume = 22.4 litres at STP)

The correct option is E
14