What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to a maximum vertical height of 40cm. (Take g=9.8m/s2)
A
1.4m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.7m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2.8m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
3.6m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C2.8m/s ⇒Mean position refers to the bottom most position of the bob.
Applying energy conservation between initial to final position, Loss in KE of bob=Gain in PE of bob ⇒12mv2=mgh Or, v=√2×g×h v=√2×9.8×0.4=√784100 ∴v=2.8m/s