What is the velocity of the particle of the string at the position x = 1.5 cm when $t = \frac{9}{8} s$ ?

0 cm/s

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1 cm/s

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2 cm/s

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4 cm/s

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Solution

The correct option is A 0 cm/s
$y = A s i n (k x) c o s (ω t)$
Thus velocity of particle is given by $v = \frac{d v}{d t} = ω A s i n (k x) s i n (ω t)$
Thus $v (x = 1.5, t = 9 / 8) = 0$

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What is the velocity of the particle of the string at the position x = 1.5 cm when t=98s ?

The correct option is A 0 cm/sy=Asin(kx)cos(ωt)Thus velocity of particle is given by v=dvdt=ωAsin(kx)sin(ωt)Thus v(x=1.5,t=9/8)=0

What is the velocity of the particle of the string at the position x = 1.5 cm when $t = \frac{9}{8} s$ ?

The correct option is A 0 cm/s
$y = A s i n (k x) c o s (ω t)$
Thus velocity of particle is given by $v = \frac{d v}{d t} = ω A s i n (k x) s i n (ω t)$
Thus $v (x = 1.5, t = 9 / 8) = 0$