What is the volume (in $c m^{3}$ ) of the prism whose base is a hexagon of side 6 cm and height $12 \sqrt{3}$ cm?

1944 \sqrt{3}

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1944

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1654 \sqrt{3}

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1654

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Solution

The correct option is B 1944
Area of prism $= A r e a o f b a s e \times h e i g h t$
Area of the hexagon of side a $= \frac{3 \sqrt{3}}{2} a^{2}$
So, area of given prism $= \frac{3 \sqrt{3}}{2} \times 6^{2} \times 12 \sqrt{3} = 1944 c m^{3}$

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