Question

What is the volume occupied by $11g$ of carbon dioxide at ${27}^{\circ }C$ and $780mm$ of $Hg$ pressure?

Answer 1

$780mm$ of $Hg=\frac{780}{760}atm$

$w=11g,M=44gmo{l}^{-1}$.
Now apply $V=\frac{w}{M}\cdot \frac{RT}{P}$ = $\frac{11\times 0.0821\times 300\times 760}{44\times 780}$ = $6litre$.