The correct option is A 14
Gram molecular mass of oxygen (O2) is 32 g, which is equal to the mass of one mole of oxygen.
At STP, the volume occupied by one mole of a gas is 22.4 litres.
Thus, 32 g of oxygen gas occupies 22.4 litres
Hence, the volume occupied by 20 g of oxygen at STP = 20×22.432 = 14 litres