What is the volume of 6 g of hydrogen at 1-5 atm and 273- C -A- undefinedB- undefinedC- undefinedD- undefined

Pressure = 1.5 atm temperature = 273 K R = 0.0821 lit.atm/mole n = given weight/molecular weight = 6/2 = 3 From ideal gas equation: PV = nRT V =nRT/P =(3*0. ...

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Byju's Answer

Standard XII

Chemistry

Dalton's Law of Partial Pressures

What is the v...

Question

What is the volume of 6g of hydrogen at 1.5atm and $273^{\circ} C$ ?

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Solution

Pressure = 1.5 atm
temperature = 273 K
R = 0.0821 lit.atm/mole
$n = \frac{g i v e n w e i g h t}{m o l e c u l a r w e i g h t}$
$= \frac{6}{2}$
= 3
From ideal gas equation: PV = nRT
$V = \frac{n R T}{P}$
$= \frac{(3 * 0.0821 * 273)}{1.5}$
= 44.8266 lit

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What is the volume of 6g of hydrogen at 1.5atm and 273∘C?

Pressure = 1.5 atm temperature = 273 K R = 0.0821 lit.atm/mole n=given weightmolecular weight =62 = 3 From ideal gas equation: PV = nRT V=nRTP =(3∗0.0821∗273)1.5 = 44.8266 lit

What is the volume of 6g of hydrogen at 1.5atm and $273^{\circ} C$ ?

Pressure = 1.5 atm
temperature = 273 K
R = 0.0821 lit.atm/mole
$n = \frac{g i v e n w e i g h t}{m o l e c u l a r w e i g h t}$
$= \frac{6}{2}$
= 3
From ideal gas equation: PV = nRT
$V = \frac{n R T}{P}$
$= \frac{(3 * 0.0821 * 273)}{1.5}$
= 44.8266 lit