What is the volume of ${C O}_{2}$ ., obtained at STP when 168 g of ${M g C O}_{3}$ is heated ?

11.2

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22.4

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33.6

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44.8

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Solution

The correct option is D 44.8
given,

$M g C O_{3} - 168 g$

When it heated

$M g C O_{3} \to M g O + C O_{2}$

at STP one mole = $22.4 l$

mass of $M g C O_{3} - 84$

moles = $\frac{168}{84} = 2$

volume of $C O_{2}$ in one mole is $22.4$

so, total volume of $C O_{2}$ - $2 \times 22.4 = 44.8$

Hence, option(d) is the correct answer.

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