What is the volume of $H N O_{2}$ consumed by urea?

12.5

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25

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50

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75

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Solution

The correct option is C $50$ mL
The number of moles of urea $\frac{0.3 g}{60 g/mol} = 0.005 mol$
Number of moles of $H N O_{2} = 2 \times$ number of moles of urea $2 \times 0.005 mol = 0.01 mol$
Molarity of $H N O_{2}$ is 0.2 M.
Volume of $H N O_{2}$ consumed $= \frac{0.01 mol}{0.2 mol/L} = 0.05 L$
Convert the volume from L to mL.
$0.05 L \times 1000 mL/L = 50 mL$

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What is the volume of HNO2 consumed by urea?

The correct option is C 50 mLThe number of moles of urea 0.3 g 60 g/mol= 0.005 molNumber of moles of HNO2=2× number of moles of urea 2× 0.005 mol= 0.01 molMolarity of HNO2 is 0.2 M.Volume of HNO2 consumed = 0.01 mol 0.2 mol/L= 0.05 LConvert the volume from L to mL. 0.05 L × 1000 mL/L = 50 mL

What is the volume of $H N O_{2}$ consumed by urea?