Question

What is the volume of occupied by 3 g of hydrogen at 1.5 atm and ${273}^{o}C$?

• A. 52.5 litre
• B. 44.8 litre
• C. 59.72 litre
• D. None of these

Answer 1

The correct option is B 44.8 litre

Given, $m=3g$
$P_2=1.5atm$
$T_2={273}^{o}C$
$=273+273$
$=546K$
$n=\frac{3}{2}=1.5moles$
$V_2=?$
At STP,
For 1 mole, At given conditions (1 mole)
$\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}$
$\frac{1\times 22.4}{273}=\frac{1.5\times V_2}{546}$
$V_2=\frac{22.4\times 2}{1.5}l$
But number of moles $=1.5$
$\therefore$ For 1 mole volume occupied is
$\frac{22.4\times 2}{1.5}l$
For 1.5 mole volume occupied
$=\frac{22.2\times 2}{1.5}\times 1.5=44.8l$