Question

What is the volume of solution $\left(\text{in L}\right)$ containing $1\text{g mole}$ of sugar that will give rise to an osmotic pressure of $1\text{atm}$ at ${27}^{\circ }\text{C}$ ?
(Given : $R=0.082{\text{L atm K}}^{-1}{\text{mol}}^{-1}$ )

Answer 1

Applying the equation
$\Pi =cRT=\frac{n}{V}RT\Rightarrow V=\frac{n}{\Pi }\times R\times T$
Given, $n=1,\Pi =1\text{atm}$, $R=0.082{\text{L atm K}}^{-1}{\text{mol}}^{-1}$ and $T=300\text{K}$
$\therefore V=\frac{1}{1}\times 0.082\times 300=24.6\text{L}$