What is the volume strength of 1.5 N $H_{2} O_{2}$ solution?

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Solution

Volume strength refers to the volume of oxygen gas evolved by one volume of $H_{2} O_{2}$ . This oxygen gas evolved in the reaction is:
$2 H_{2} O_{2} \to 2 H_{2} O + O_{2}$
Now, 1.5 N of $H_{2} O_{2}$ will contain 1.5 equivalents of $H_{2} O_{2}$ per litre.1.5 equivalents of $H_{2} O_{2}$ means $\frac{1.5}{2} = 0.75$ moles of $H_{2} O_{2}$ . Now 0.75 moles of $H_{2} O_{2}$ forms $\frac{0.75}{2}$ moles of $O_{2}$ .Therefore the 1.5 N solution of $H_{2} O_{2}$ forms 0.375 moles of $O_{2}$ . If we assume that the reaction is taking place at STP, then 1 mole of oxygen gas will occupy a volume of 22.4 litres. Therefore, 0.375 moles of oxygen will occupy a volume of 8.4 litres.

Thus, volume strength of 1.5 N $H_{2} O_{2}$ solution is 8.4 litres.

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