Question

What is the wavelength of $H_{\beta }$ line of the Balmer series of hydrogen spectrum? (R = Rydberg constant)

• A. 36/5R
• B. 5R/36
• C. 3R/16
• D. 16/3R

Answer 1

The correct option is D 16/3R

$H_{\beta }ofBalmerseries\Rightarrow n=4ton=2$

$\frac{1}{\lambda }=R[\frac{1}{(2{)}^2}-\frac{1}{(4{)}^2}]$

$\frac{1}{\lambda }=\frac{3R}{16}$

$\Rightarrow \lambda =\frac{16}{3R}$