Question

What is the weight by volume percentage of $3N{H}_2{SO}_4$ solution?

• A. $5$ %
• B. $10$ %
• C. $14.7$ %
• D. $20$ %

Answer 1

The correct option is C $14.7$ %

$\text{Normality}=\frac{\text{Weight}}{\text{Equivalent weight}}\times \frac{1}{V\left(L\right)}$

$⟹3N=\frac{\omega }{\frac{98}{2}}\times \frac{1000}{V\left(mL\right)}$

$⟹\frac{\omega }{V}\times 1000=\frac{3\times 98}{2}$ $⟹\frac{\omega }{V}\times 100=\frac{147}{10}$

Therefore, $\frac{\omega }{V}$% $=14.7$%.