What is the weight (in g) of $N a_{2} C O_{3}$ (molar mass $= 106$ ) present \ in\ $250 m l, o f i t s$ 0.2\ M$ solutions?

0.53

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5.3

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1.06

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10.6

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Solution

The correct option is B $5.3$
$C o n c e n t r a t i o n = \frac{Moles of {N a}_{2} C O_{3}}{Volume of solvent}$

$M a s s o f {N a}_{2} C O_{3} = m o l a r m a s s \times m o l e s o f {N a}_{2} C O_{3}$

$= 106 g {m o l}^{- 1} 0.250 L \times 0.2 m o l L^{- 1}$

$= 5.3 g$

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