Question

What is the weight (in grams) of $H_{2}S{O}_4$ are present in $0.25$ moles of $H_{2}S{O}_4$?

• A. $0.25$
• B. $25.00$
• C. $24.50$
• D. $2.45$

Answer 1

Answer: (C)

$24.50$

No. of moles = $\frac{givenmass}{molecularweight}$

Molar weight of $H_{2}S{O}_4=98gm/mole$
Since,$1$ mole of $H_{2}S{O}_4$ contains $98gm$
$\therefore 0.25$ mole of $H_{2}S{O}_4$ contains $\Rightarrow 98\times 0.25=24.50gm$