What is the weight of oxygen required for the complete combustion of 2.8 kg of ethylene

2.8 kg

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6.4 kg

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9.6 kg

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96 kg

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Solution

The correct option is B 6.4 kg
$C_{2} H_{4} + 20_{2} \to 2 C O_{2} + 2 H_{2} O$
$∵ 2 g m C_{2} H_{4}$ requires 64gm oxygen
$∴ 2.8 \times 10^{3} g m C_{2} H_{4} r e q u i r e s = \frac{64}{28} \times 2.8 \times 10^{3} g m$
$= 6.4 \times 10^{3} f m = 6.4 k g$

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