what is the weight percent of ethanol in a solution made by dissolving 5.3g of ethanol in 85g of water

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Solution

$W e i g h t % = \frac{W e i g h t o f t h e s o l u t e}{W e i g h t o f t h e s o l u t i o n} \times 100 W e i g h t o f t h e s o l u t e (e t h a n o l) = 5.3 g W e i g h t o f t h e s o l u t i o n = 85 + 5.3 = 90.3 W e i g h t % = \frac{5.3}{90.3} \times 100 = 5.87 %$

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what is the weight percent of ethanol in a solution made by dissolving 5.3g of ethanol in 85g of water

Weight % = Weight of the soluteWeight of the solution × 100Weight of the solute (ethanol) = 5.3 gWeight of the solution = 85 + 5.3 =90.3Weight % = 5.390.3 × 100 =5.87 %

$W e i g h t % = \frac{W e i g h t o f t h e s o l u t e}{W e i g h t o f t h e s o l u t i o n} \times 100 W e i g h t o f t h e s o l u t e (e t h a n o l) = 5.3 g W e i g h t o f t h e s o l u t i o n = 85 + 5.3 = 90.3 W e i g h t % = \frac{5.3}{90.3} \times 100 = 5.87 %$