Question

What is the work done by an external force in stretching a spring having spring constant k=100 N/m by 10 cm from its unstretched position?

Answer 1

Dear Student,
$$\begin{gathered} Given, \\ K=100N/m \\ x=10cm \\ 100cm=1m \\ Then, \\ x=10/100m \\ x=0.1m \\ {W}_s=\frac{1}{2}K\left[\right(x_i{)}^2-\left(x_f{)}^2\right] \\ {W}_s=\frac{1}{2}\times 100\left[\right(0{)}^2-(0.1{)}^2]Joule \\ {W}_s=50[0-0.01]Joule \\ {W}_s=50\times 0.01Joule \\ {W}_s=0.5Joule \end{gathered}$$
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