wiz-icon
MyQuestionIcon
MyQuestionIcon
10
You visited us 10 times! Enjoying our articles? Unlock Full Access!
Question

What is the work done to lift an object weighing 100 g to a height of 50 m from an initial height of 20 m? (Assume g =10 m s−2)


A

20 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

30 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

50 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

70 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

30 J


Here, work done to lift an object is the work done against the gravitational force.

Force required to lift the object is equal to the product of mass and acceleration due to gravity (g =10 m s2).

Here, mass of the object, m = 100 g = 0.1 kg

Intial height = 20 m

Final height = 50 m

So, force = m×g = 0.1×10 = 1 N

Work done = Force × Displacement

= 1 × (50-20)

= 30 J

Work done to lift the object is 30 J.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Work
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon