What is the zero that is common to the polynomials $p (x) = x^{2} - 2 x + 1$ and $q (x) = x^{2} - 3 x + 2 ?$

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Solution

The correct option is A 1
Given, $P (x) = x^{2} - 2 x + 1, q (x) = x^{2} - 3 x + 2$
Let the common zero be a
$∴$ P(a) = q(a) = 0
Now $a^{2} - 2 a + 1 = a^{2} - 3 a + 2$
$\Rightarrow - 2 a + 1 = - 3 a + 2$
$\Rightarrow a = 1$

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