What is to be added to $2 a^{3} + 4 a b^{2} - 5 b^{3} - 6 a^{2} b$ to get $3 a^{3} - 4 a^{2} b + 11 a b^{2} + b^{3}$ ?

a^{3} + 2 a^{2} b + 7 a b^{2} - 6 b^{3}

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a^{3} - 2 a^{2} b - 7 a b^{2} + 6 b^{3}

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a^{3} + 2 a^{2} b + 7 a b^{2} + 6 b^{3}

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a^{3} + 2 a^{2} b - 7 a b^{2} + 6 b^{3}

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Solution

The correct option is C $a^{3} + 2 a^{2} b + 7 a b^{2} + 6 b^{3}$
$3 a^{3} - 4 a^{2} b + 11 a b^{2} + b^{3}$
$- 2 a^{3} + 6 a^{2} b - 4 a b^{2} + 5 b^{3} - -------------------------- -$
$a^{3} + 2 a^{2} b + 7 a b^{2} + 6 b^{3}$

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