What is value of y so that the line through (3, y) and (2, 7) is parallel to the line passing through (- 1 ,4) and (0, 6)?

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Solution

The correct option is A 9
$m_{1} = m_{2}$ (for parallel lines)
$\Rightarrow \frac{7 - y}{2 - 3} = \frac{6 - 4}{0 + 1} \Rightarrow \frac{7 - y}{- 1} = \frac{2}{1} \Rightarrow y = 9$

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Similar questions

The value of y, for the line passing through (3, y) and (2, 7) is parallel to the line passing through (-1, 4) and (0, 6) is:

y

(3, y)

(2, 7)

(- 1, 4)

(0, 6)

y

(3, y)

(2, 7)

(- 1, 4)

(0, 6)

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