1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Factors Affecting Adsorption
What is work ...
Question
What is work done by 0.2 mole of gas at room temperature to double it's volume during isobaric process ? (R= 2 cal/mol C)
Open in App
Solution
Suggest Corrections
33
Similar questions
Q.
What is the work done by
0.2
mole of a gas at room temperature to double volume during isobaric process (take
R
=
2
c
a
l
m
o
l
−
1
K
−
1
)
Q.
Calculate the work done by
0.1
mole of a gas at
27
o
C
to double its volume at constant pressure isobaric process
(
R
=
2
c
a
l
m
o
l
−
1
K
−
1
)
Q.
Work done by
0.1
mole
of a gas at
27
∘
C
to double its volume at constant pressure is
[Take
R
=
2
cal mol
−
1
K
−
1
]
Q.
Work done by
0.1
mole
of a gas at
27
∘
C
to double its volume at constant pressure is
[Take
R
=
2
cal mol
−
1
K
−
1
]
Q.
Two moles of a gas is expanded to double its volume by two different processes. One is isobaric and the other is isothermal. If
w
1
and
w
2
are the works done respectively, then
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
All About Adsorption
CHEMISTRY
Watch in App
Explore more
Factors Affecting Adsorption
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app