Question

What is X in the following nuclear reaction ${}_7{N}^{14}{+}_1{H}^1{\to }_8{O}^{15}+X$

• A. ${}_{+1}{e}^0$
• B. ${}_0{n}^1$
• C. $\gamma$
• D. ${}_{-1}{e}^0$

Answer 1

The correct option is C $\gamma$

${}_7{N}^{14}{+}_1{H}^1{\to }_8{O}^{15}+\gamma$