Question

What is X in the nuclear reaction?
${}_7{N}^{14}{+}_1{H}^1{\to }_8{O}^{15}+X$

• A. ${}_{1}H\&2$
• B. ${}_0{n}^1$
• C. $\gamma$
• D. $-1e^0$

Answer 1

Answer: (C)

$\gamma$

${}_7{N}^{14}{+}_1{H}^1{\to }_8{O}^{15}{+}_Z{X}^A$
Equating mass number of both sides,
14 + 12 = 15 + A
$\therefore$ A = 0
Equating atomic number of both sides,
7 + 1 = 8 + Z
$\therefore$ Z = 0
The particle is $\gamma$.