What is Y from the below reaction- CH 3- CH 2 OH Alkaline KMnO 4- Heat - Or acidif ied K 2 Cr 2 O 7- Heat YA- CH 3 COOHB- H 2 C - CH 2C- CH 3 CH 2 COOHD- CH 3- OH

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Oxidation

What is Y fro...

Question

What is Y from the below reaction?
$C H_{3} - C H_{2} O H A l k a l i n e K M n O_{4} + H e a t - ----------------- \to O r a c i d i f i e d K_{2} C r_{2} O_{7} + H e a t Y$

C H_{3} C O O H

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H_{2} C = C H_{2}

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C H_{3} C H_{2} C O O H

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C H_{3} - O H

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Solution

The correct option is A $C H_{3} C O O H$
$C H_{3} C H_{2} O H$ is oxidized to $C H_{3} C O O H$ in the presence of (Alkaline $K M n O_{4}$ or Acidified $K_{2} C r_{2} O_{7}$ ) + heat.
$C H_{3} - C H_{2} O H A l k a l i n e K M n O_{4} + H e a t - ----------------- \to O r a c i d i f i e d K_{2} C r_{2} O_{7} + H e a t C H_{3} C O O H$
Hence, Y is $C H_{3} C O O H$ .

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What is Y in the reaction given below ?

$C H_{3} - C H_{2} O H Alkaline K M n O_{4} +Heat - --------------- \to or acidified K_{2} C r_{2} O_{7} +Heat Y$

Which component is $Y$ in the reaction given below?
$C H_{3} - C H_{2} - C H_{2} O H A l k a l i n e K M n O_{4} + H e a t - ----------------- \to O r a c i d i f i e d K_{2} C r_{2} O_{7} + H e a t Y$

{CH}_{3} - {CH}_{2} - Br + {CH}_{3} - {CH}_{2} - Br Na / dry ether - ------- \to The product / s formed are

Q. What is the major product of the following reaction?

H_{2} C = C H - C H_{2} O H H B r (e x c e s s) - ------- \to P r o d u c t

Q. In the given reaction

$C H_{3} - O | | C - O - C H_{3} | C | C H_{3} - C H_{3} N a / C_{2} H_{5} O H - ------- \to (X) + (Y)$

$[X] a n d [Y]$ respectively be:
$(a) C H_{3} - C H_{2} - O H a n d C H_{3} - C H_{3} | C | C H_{3} - O H$
$(b) C H_{3} - C H_{2} - O H a n d C H_{3} - C | C H_{3} = C H_{2}$
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(d) all the above

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What is Y from the below reaction? CH3−CH2OHAlkaline KMnO4+Heat−−−−−−−−−−−−−−−−−−→Or acidified K2Cr2O7+HeatY

The correct option is A CH3COOHCH3CH2OH is oxidized to CH3COOH in the presence of (Alkaline KMnO4 or Acidified K2Cr2O7) + heat. CH3−CH2OHAlkaline KMnO4+Heat−−−−−−−−−−−−−−−−−−→Or acidified K2Cr2O7+HeatCH3COOH Hence, Y is CH3COOH.

What is Y from the below reaction?
$C H_{3} - C H_{2} O H A l k a l i n e K M n O_{4} + H e a t - ----------------- \to O r a c i d i f i e d K_{2} C r_{2} O_{7} + H e a t Y$