What is Y in the reaction given below- CH 3- CH 2 OH Alkaline KM nO 4- Heat - or acidified K 2 Cr 2 O 7- Heat - YA- CH 3 COOHB- H 2 C - CH 2C- HCOOHD- CH 3 CH 2 COOH

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Oxidation

What is Y in ...

Question

What is Y in the reaction given below?

$C H_{3} - C H_{2} O H Alkaline K M n O_{4} +Heat - ---------------- \to or acidified K_{2} C r_{2} O_{7} +Heat Y$

CH₃COOH

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H₂C-CH₂

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CH₃CH₂COOH

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HCOOH

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Solution

The correct option is A
CH₃COOH

$C H_{3} - C H_{2} O H$ is oxidized to $C H_{3} C O O H$ in the presence of alkaline $K M n O_{4}$ + heat or acidified $K_{2} C r_{2} O_{7}$ + heat.

$C H_{3} - C H_{2} O H Alkaline K M n O_{4} +Heat - ---------------- \to or acidified K_{2} C r_{2} O_{7} +Heat C H_{3} C O O H$

Hence, Y is $C H_{3} C O O H$

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Similar questions

Q. What is Y from the below reaction?

C H_{3} - C H_{2} O H A l k a l i n e K M n O_{4} + H e a t - ----------------- \to O r a c i d i f i e d K_{2} C r_{2} O_{7} + H e a t Y

Which component is $Y$ in the reaction given below?
$C H_{3} - C H_{2} - C H_{2} O H A l k a l i n e K M n O_{4} + H e a t - ----------------- \to O r a c i d i f i e d K_{2} C r_{2} O_{7} + H e a t Y$

Q. 1-butyne on reaction with hot alkaline

K M n O_{4}

gives:

{CH}_{3} - {CH}_{2} - Br + {CH}_{3} - {CH}_{2} - Br Na / dry ether - ------- \to The product / s formed are

Q. What is the major product of the following reaction?

H_{2} C = C H - C H_{2} O H H B r (e x c e s s) - ------- \to P r o d u c t

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What is Y in the reaction given below? CH3−CH2OHAlkaline KMnO4+Heat−−−−−−−−−−−−−−−−−→or acidified K2Cr2O7+Heat Y

The correct option is A CH3COOH CH3−CH2OH is oxidized to CH3COOH in the presence of alkaline KMnO4 + heat or acidified K2Cr2O7+ heat. CH3−CH2OHAlkaline KMnO4+Heat−−−−−−−−−−−−−−−−−→or acidified K2Cr2O7+Heat CH3COOH Hence, Y is CH3COOH

What is Y in the reaction given below?

$C H_{3} - C H_{2} O H Alkaline K M n O_{4} +Heat - ---------------- \to or acidified K_{2} C r_{2} O_{7} +Heat Y$