What is Z in the following reaction sequence?
$C_{6} H_{5} {N H}_{2} (i) N a {N O}_{2} + H C l / 273 K - ------------------------------- \to (i i) H_{3} {P O}_{2} + H_{2} O (i i i) C O, H C l; a n h y d r o u s A l {C l}_{3} / C u C l Z$

C_{6} H_{5} {C O}_{2} H

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C_{6} H_{5} O H

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C_{6} H_{5} C H O

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C_{6} H_{6}

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Solution

The correct option is C $C_{6} H_{5} C H O$
Diazotization of aniline with nitrous acid in cold conditions gives benzene diazonium chloride. On treatment with $H_{3} P O_{2}$ , diazo group is replaced with H. This is followed by Gatterman - Koch formylation to form benzaldehyde.

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Similar questions

C_{6} H_{6} \to C_{6} H_{5} {C H}_{3}

C_{6} H_{5} {N H}_{2}

C_{6} H_{5} {N H C H}_{3}

C_{6} H_{5} {C H}_{2} {N H}_{2}

C_{6} H_{5} {N H}_{2}

C_{6} H_{5} {N H C H}_{3}

C_{6} H_{5} {C H}_{2} {N H}_{2}

2 C_{6} H_{5} C H O + {O H}^{-} ⟶ C_{6} H_{5} C O O^{-} + C_{6} H_{5} {C H}_{2} O H

A : 2 C_{6} H_{5} C H O + K O H ⟶ C_{6} H_{5} C O O K + C_{6} H_{5} {C H}_{2} O H

B : 3 {C l}_{2} + 6 K O H ⟶ 5 K C l + K C l O_{3} + 3 H_{2} O

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