What least number $x$ must be subtracted from $797$ , so that the number $(797 - x)$ on being divided by $8, 9$ and $11$ leaves in each case, the same remainder $4$ ?

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Solution

The correct option is B $1$
LCM of $8, 9 a n d 11 = 8 \times 9 \times 11 = 792$
$∴ 797 - x = 792 + 4$
$\Rightarrow x = 797 - 796 = 1$

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