Question

What least value should be given to * so that the number 915*26 is divisible by 9?

(a) 1
(b) 4
(c) 2
(d) 6

Answer 1

(b) 4
A number is divisible by 9 if the sum of its digits is a multiple of 9.
Sum of the given digits = 9 + 1 + 5 + 2 + 6 = 23
We know that multiple of 9 greater than 23 is 27.
∴ 27 − 23 = 4
Hence, the smallest required digit is 4.