Question

What length of tarpaulin 3 m wide will be required to make a conical tent of height 8 m and base radius 6 m? Assum that the extra length of material will be required for stitching margins and wastage in cutting is approximately 20 cm.(Use $\pi =3.14)$

Answer 1

Height of the conical tent (h)= 8 m

and radius of the base (r)= 6 m

$\therefore Slantheight\left(l\right)=\sqrt{r^2+h^2}=\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10m$

Now curved surface area of the tent= $\pi rl$ =$3.14\times 6\times 10=188.4m$

Width of tarpaulin used = 3 m

$\therefore Length=\frac{188.4}{3}=62.8m$

Extra length required = 20 cm=0.2 m

$\therefore$ Total length of tarpaulin=62.8+0.2

=63 m