Height (h) of the conical tent = 8 m
Radius (r) of base of the tent = 6 m
Slant height (l) of the tent
=√r2+h2
=(√62+82) m=(√100) m=10 m
CSA of conical tent
= πrl
=(3.14×6×10) m2
=188.4 m2
Let the length of tarpaulin sheet required be l.
As 20 cm will be wasted, the effective length will be (l−0.2) m.
Breadth of tarpaulin = 3 m
Area of sheet = CSA of the tent
[(l−0.2)×3] m2=188.4 m2 [Area of rectangular sheet = l×b]
(l−0.2) m = 62.8 m
l=63 m
Therefore, the length of the required tarpaulin sheet will be 63 m.