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Question

What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm.

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Solution

h=8m, r=6m, l=r2+h2
=62+82
100=10m
CSA =πrl=(3.14×6×10)m2=188.4m2
Let the length of sheet required =x
Breadth =3m
Area =l×b=3×x=3x
20cm of length will be wasted:
Effective length =(x20100)
=80100xm
CSA of tent = Area of sheet
188.4=(80x100)3
80100x=62.810m, l=6288m
l=63m

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