Question

What load will be lifted by an effort of $12$ $N$ if the velocity ratio is $18$ and the efficiency of the machine at this load is 60%?

• A. 1N
• B. .130N
• C. 1.30N
• D. 13N

Answer 1

The correct option is B .130N

$\eta =\frac{load}{effort\ast VR}\ast 100$
$load=\eta \ast effort\ast VR=0.6\ast 12\ast 18=130N$