(x2−a2)2(x2+b2)2+c4(y2−a2)2=0
This being the sum of two perfect squares, each term must be zero
(x2−a2)2(x2−b2)2=0 or (x2−a2)(x2−b2)=0
or (x−a)(x+a)(x−b)(x+b)=0
and c4(y2−a2)2=0
or c2(y2−a2)2=0
∵c≠0∴y=±a
∴x=±a,±b
y=±a
As both of these must simultaneously satisfy, the given line represents 8 points which we get as a result of different combination of (1) and (2) , namely
(±a,±a),(±b,±a)