What mass (nearest integer) of phosphoric acid, $H_{3} P O_{4}$ is required to prepare $550$ mL of $0.40 N$ solution? (assuming complete neutralisation of acid)

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Solution

The complete neutralization of $H_{3} P O_{4}$ means it will act as a tribasic acid.

$0.40 N H_{3} P O_{4}$ corresponds to $\frac{0.40}{3} M H_{3} P O_{4}$ .

$1 L$ of solution will contain $\frac{0.40}{3}$ moles.
$550$ mL of solution will contain $\frac{0.40 \times 550}{3 \times 1000}$ moles.

This corresponds to $H_{3} P O_{4} = \frac{0.40 \times 550 \times 98}{3 \times 1000} = 7.187$ g.

The nearest integer is $7$ .

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