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Byju's Answer
Standard XII
Chemistry
Planck's Quantum Hypothesis
What mass of ...
Question
What mass of
14
C
with
T
50
%
=
5730
years has activity equal to one curie?
A
0.2244
g
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B
0.4244
g
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C
0.3244
g
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D
0
.
6729
g
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Solution
The correct option is
C
0.2244
g
1
C
i
=
3.7
×
10
10
d
p
s
t
50
=
5730
y
e
a
r
s
=
5730
×
3.1536
×
10
7
s
∴
λ
=
0.693
t
50
=
0.693
5730
×
3.1536
×
10
7
s
−
1
−
d
N
d
t
=
λ
N
=
λ
w
×
6.02
×
10
23
14
3.7
×
10
10
=
0.693
×
w
×
6.02
×
10
23
5730
×
3.1536
×
10
7
×
14
w
=
0.2244
g
Suggest Corrections
0
Similar questions
Q.
The curie was originally intended to be the activity of one gram of radium-226. The actual weight of radium which is equal to one curie is (in gm)
T
50
(Radius-226) = 1620 years
One curie =
3.7
×
10
10
disintegrations (of atoms) per second (dps)
One year =
3.154
×
10
7
seconds
Q.
Before
1900
, the activity per mass of atmosphere carbon due to the presence of
14
C
averaged about
0.255
B
q
per gram of
C
. What fraction of carbon atoms were
14
C
?
Given: Half life is
5730
years.
Q.
1 g of
14
C
from an archaeological sample gives 9.4 counts
m
i
n
−
1
. 1 g of
14
C
from a recently cut tree given 15.3 counts
m
i
n
−
1
under the same conditions. How old is the archaeological sample? (
T
50
of
14
C
is 5730 years).
Q.
The lowest level
14
C
activity for experimental detection is 0.03 dis/min -g of
14
C
. The activity of
14
C
in atmosphere is 15 dis/min-g of
14
C
. The maximum age of an object that can be determined by
14
C
method is:
(
t
1
/
2
o
f
14
C
=
5730
y
e
a
r
)
Q.
Show that the mass of radium
(
88
R
a
226
)
with an activity of
1
curie is almost
1
gram
[
T
1
2
=
1600
years].
[
1
curie
=
3.7
×
10
10
disintegrations per second].
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